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Since the balanced equation is C4H8S2 + 9O2 --> 4CO2 + 4H2O + 2SO3, the ratio is going to be 1:9.

C4H8S2: O2:

C: (4x12) + H: (8x1) + S: (2x32)= 120 GFW O: (2x16) = 32 GFW

The number of grams for C4H8S2 is 63.1g. To find the number of moles you are going to divide 63.1g by 120 GFW. This equals 0.526 moles.

The number of grams for O2 is 209g. To find the number of moles you are going to divide 209g by 32 GFW. This equals 6.531 moles.

Since the ratio that we have already has one of the compounds being one we can leave the ratio as 1:9, C4H8S2 to O2.

Since you have a 1:9 ratio the number of moles of O2 should be 9 times that of C4H8S2. Since you have 0.526 moles of C4H8S2 and 6.531 moles of O2, and you are supposed to have a 1:9 ratio, the number of moles for O2 should be 4.73 based on the number of moles of C4H8S2 (0.526x9). Therefore, you have an excess of O2 which means that you do not have the sufficient amount of C4H8S2 making it the limiting reagent.

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**Question:**For the balanced equation C4H8S2 + 9O2 --> 4CO2 + 4H2O + 2SO3, what would be the limiting reagent if 63.1 grams of C4H8S2 were reacted with 209 grams of O2?**Step One**: Based on the coefficients of the reactants (the two compounds) find the ratio.Since the balanced equation is C4H8S2 + 9O2 --> 4CO2 + 4H2O + 2SO3, the ratio is going to be 1:9.

**Step Two**: Find the GFW of each compound (do not combine them).C4H8S2: O2:

C: (4x12) + H: (8x1) + S: (2x32)= 120 GFW O: (2x16) = 32 GFW

**Step Three:**Find the number of moles for each compound. You can do this by dividing the number of grams for one of the compounds by its GFW (do this for both compounds, separately).__C4H8S2:__The number of grams for C4H8S2 is 63.1g. To find the number of moles you are going to divide 63.1g by 120 GFW. This equals 0.526 moles.

__O2:__The number of grams for O2 is 209g. To find the number of moles you are going to divide 209g by 32 GFW. This equals 6.531 moles.

**Step Four**: Take the ratio and rewrite it so that it’s a one to something ratio (1:?). This is done by dividing both numbers in the ratio by the smaller number in the ratio.Since the ratio that we have already has one of the compounds being one we can leave the ratio as 1:9, C4H8S2 to O2.

**Step Five**: Whichever compound is the “one part” of the ratio, multiply its number of moles by the other number in the ratio. If the product is greater than the number of moles in the second compound, the second compound is the limiting reagent. If the product is less than the number of moles in the second compound, the first compound is the limiting reagent.Since you have a 1:9 ratio the number of moles of O2 should be 9 times that of C4H8S2. Since you have 0.526 moles of C4H8S2 and 6.531 moles of O2, and you are supposed to have a 1:9 ratio, the number of moles for O2 should be 4.73 based on the number of moles of C4H8S2 (0.526x9). Therefore, you have an excess of O2 which means that you do not have the sufficient amount of C4H8S2 making it the limiting reagent.

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