## I'm sorry but the answer that you got was incorrect.

Let’s go through the steps together to help you understand.

Since the balanced equation is 2NH3 + CO2 --> CO(NH2)2 + H2O, the ratio is going to be 2:1.

NH3: CO2:

N: (1x14) + H: (3x1) = 17 GFW C: (1x12) + O: (2x16) = 44 GFW

The number of grams for NH3 is 34.7g. To find the number of moles you are going to divide 34.7g by 14 GFW. This equals 2.041 moles.

The number of grams for CO2 is 68.5g. To find the number of moles you are going to divide 68.5g by 44 GFW. This equals 1.557 moles.

Since the ratio that we have already has one of the compounds being one we can leave the ratio as 2:1 NH3 to CO2.

Since you have a 2:1 ratio the number of moles of NH3 should be double that of CO2. Since you have 2.041 moles of NH3 and 1.557 moles of CO2, and you are supposed to have a 2:1 ratio, the number of moles for NH3 should be 3.114 based on the number of moles of CO2 (1.557x2). Therefore, you do not have the sufficient amount of NH3 making it the limiting reagent.

**Question:**For the balanced equation 2NH3 + CO2 --> CO(NH2)2 + H2O, if 34.7 grams of NH3 is reacted with 68.5 grams of CO2, how many grams of H2O would be produced?**Step One**: Find the the limiting reagent.__Here are the steps to finding the limiting reagent__**Step One**: Based on the coefficients of the reactants (the two compounds) find the ratio.Since the balanced equation is 2NH3 + CO2 --> CO(NH2)2 + H2O, the ratio is going to be 2:1.

**Step Two**: Find the GFW of each compound (do not combine them).NH3: CO2:

N: (1x14) + H: (3x1) = 17 GFW C: (1x12) + O: (2x16) = 44 GFW

**Step Three:**Find the number of moles for each compound. You can do this by dividing the number of grams for one of the compounds by its GFW (do this for both compounds, separately).__NH3:__The number of grams for NH3 is 34.7g. To find the number of moles you are going to divide 34.7g by 14 GFW. This equals 2.041 moles.

__CO2:__The number of grams for CO2 is 68.5g. To find the number of moles you are going to divide 68.5g by 44 GFW. This equals 1.557 moles.

**Step Four**: Take the ratio and rewrite it so that it’s a one to something ratio (1:?). This is done by dividing both numbers in the ratio by the smaller number in the ratio.Since the ratio that we have already has one of the compounds being one we can leave the ratio as 2:1 NH3 to CO2.

**Step Five**: Whichever compound is the “one part” of the ratio, multiply its number of moles by the other number in the ratio. If the product is greater than the number of moles in the second compound, the second compound is the limiting reagent. If the product is less than the number of moles in the second compound, the first compound is the limiting reagent.Since you have a 2:1 ratio the number of moles of NH3 should be double that of CO2. Since you have 2.041 moles of NH3 and 1.557 moles of CO2, and you are supposed to have a 2:1 ratio, the number of moles for NH3 should be 3.114 based on the number of moles of CO2 (1.557x2). Therefore, you do not have the sufficient amount of NH3 making it the limiting reagent.

**Step Two:**Use the limiting reagent and see what the ratio is between that and the compound in the product (this is what you are trying to figure out). Make this ratio 1:? or ?:1

Since the limiting reagent is NH3 and the balanced equation is 2NH3 + CO2 --> CO(NH2)2 + H2O, the ratio between NH3 and H2O is a 2:1 ratio.

**Step Three:**Using the ratio between the limiting reagent and the compound in the product, find the number of moles in the product's compound by multiplying/diving the limiting reagent by the non-one number in the ratio (1:

**?**).

For every 2.041 moles of NH3 (^number of moles of NH3 that we have^) we need half as many moles of H2O, as shown in the ratio, therefore, we divide the number of moles of NH3 by 2 to get 1.021 moles of H2O.

**Step Four:**Once you know how many moles of the compound in the product you have, turn the moles back into grams. This allows you to answer the question of how much of ___ compound is able to be produced.

To turn the moles back into grams we used the equation grams=(moles)(GFW).

GFW of H2O: H: (2x1) + O: (1x16)= 18 GFW grams=(1.021moles)(18GFW) ---> grams=18.378g

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