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Let’s go through the steps together to help you understand.

Since the balanced equation is 2HNO3 + NO --> 3NO2 +H2O, the ratio is going to be 2:1.

HNO3: NO:

H: (1x1) + N: (1x14) + O: (3x16) = 63 GFW N: (1x14) + O: (1x16) = 30 GFW

The number of grams for HNO3 is 98.1g. To find the number of moles you are going to divide 98.1g by 63 GFW. This equals 1.557 moles.

The number of grams for NO is 18.4g. To find the number of moles you are going to divide 18.4g by 30 GFW. This equals 0.613 moles.

Since the ratio that we have already has one of the compounds being one we can leave the ratio as 2:1 HNO3 to NO.

Since you have a 2:1 ratio the number of moles of HNO3 should be double that of NO. Since you have 1.557 moles of HNO3 and 0.613 moles of NO, and you are supposed to have a 2:1 ratio, the number of moles for HNO3 should be 1.226 based on the number of moles of NO (0.613x2). Therefore, you have an excess of HNO3 meaning that you do not have the sufficient amount of NO making it the limiting reagent.

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**Question:**For the balanced equation 2HNO3 + NO --> 3NO2 +H2O, what would be the limiting reagent if 98.1 grams of HNO3 were reacted with 18.4 grams of NO?**Step One**: Based on the coefficients of the reactants (the two compounds) find the ratio.Since the balanced equation is 2HNO3 + NO --> 3NO2 +H2O, the ratio is going to be 2:1.

**Step Two**: Find the GFW of each compound (do not combine them).HNO3: NO:

H: (1x1) + N: (1x14) + O: (3x16) = 63 GFW N: (1x14) + O: (1x16) = 30 GFW

**Step Three:**Find the number of moles for each compound. You can do this by dividing the number of grams for one of the compounds by its GFW (do this for both compounds, separately).__HNO3:__The number of grams for HNO3 is 98.1g. To find the number of moles you are going to divide 98.1g by 63 GFW. This equals 1.557 moles.

__NO:__The number of grams for NO is 18.4g. To find the number of moles you are going to divide 18.4g by 30 GFW. This equals 0.613 moles.

**Step Four**: Take the ratio and rewrite it so that it’s a one to something ratio (1:?). This is done by dividing both numbers in the ratio by the smaller number in the ratio.Since the ratio that we have already has one of the compounds being one we can leave the ratio as 2:1 HNO3 to NO.

**Step Five**: Whichever compound is the “one part” of the ratio, multiply its number of moles by the other number in the ratio. If the product is greater than the number of moles in the second compound, the second compound is the limiting reagent. If the product is less than the number of moles in the second compound, the first compound is the limiting reagent.Since you have a 2:1 ratio the number of moles of HNO3 should be double that of NO. Since you have 1.557 moles of HNO3 and 0.613 moles of NO, and you are supposed to have a 2:1 ratio, the number of moles for HNO3 should be 1.226 based on the number of moles of NO (0.613x2). Therefore, you have an excess of HNO3 meaning that you do not have the sufficient amount of NO making it the limiting reagent.

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