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Question: For the balanced equation PCl3 + 3H2O --> H3PO3 + 3HCl, if the reaction of 71.2 grams of H2O produces 108 grams of HCl, what is the percent yield?
Step One: Identify the limiting reagent. (the question only gives you one of the reactants, therefore, making that compound the limiting reagent)
The limiting reagent is H2O
Step Two: Find the theoretical yield.
Question: For the balanced equation PCl3 + 3H2O --> H3PO3 + 3HCl, if the reaction of 71.2 grams of H2O produces 108 grams of HCl, what is the percent yield?
Step One: Identify the limiting reagent. (the question only gives you one of the reactants, therefore, making that compound the limiting reagent)
The limiting reagent is H2O
Step Two: Find the theoretical yield.
Here are the steps to finding the theoretical yield
Step One: Use the limiting reagent and see what the ratio is between that and the compound in the product (this is what you are trying to figure out). Make this ratio 1:? or ?:1
Since the limiting reagent is H2O and the balanced equation is PCl3 + 3H2O --> H3PO3 + 3HCl, the ratio between H2O and HCl is a 3:3 or a 1:1 ratio.
Step Two: Using the ratio between the limiting reagent and the compound in the product, find the number of moles in the product's compound by multiplying/diving the limiting reagent by the non-one number in the ratio (1:?).
For every 3.956 moles of H2O (^number of moles of H2O that we have^) we need the same number of moles of HCl, as shown in the ratio, therefore, we keep the number of moles of HCl the same and get 3.956 moles of HCl.
Step Three: Once you know how many moles of the compound in the product you have, turn the moles back into grams. This allows you to answer the question of how much of ___ compound is able to be produced.
To turn the moles back into grams we used the equation grams=(moles)(GFW).
GFW of HCl: H: (1x1) + Cl: (35.5) = 36.5 GFW grams=(3.956moles)(36.5GFW) ---> grams=144.394g
Step One: Use the limiting reagent and see what the ratio is between that and the compound in the product (this is what you are trying to figure out). Make this ratio 1:? or ?:1
Since the limiting reagent is H2O and the balanced equation is PCl3 + 3H2O --> H3PO3 + 3HCl, the ratio between H2O and HCl is a 3:3 or a 1:1 ratio.
Step Two: Using the ratio between the limiting reagent and the compound in the product, find the number of moles in the product's compound by multiplying/diving the limiting reagent by the non-one number in the ratio (1:?).
For every 3.956 moles of H2O (^number of moles of H2O that we have^) we need the same number of moles of HCl, as shown in the ratio, therefore, we keep the number of moles of HCl the same and get 3.956 moles of HCl.
Step Three: Once you know how many moles of the compound in the product you have, turn the moles back into grams. This allows you to answer the question of how much of ___ compound is able to be produced.
To turn the moles back into grams we used the equation grams=(moles)(GFW).
GFW of HCl: H: (1x1) + Cl: (35.5) = 36.5 GFW grams=(3.956moles)(36.5GFW) ---> grams=144.394g
Step Three: Plug in known information into equation shown below
Percentage Yield = (Actual Yield/Theoretical Yield) x 100%
Percentage Yield = (108grams/144.394grams) x 100%
Percentage Yield = 74.8%
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Percentage Yield = (Actual Yield/Theoretical Yield) x 100%
Percentage Yield = (108grams/144.394grams) x 100%
Percentage Yield = 74.8%
click here to go back to the quiz